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  • 1
    Electronic Resource
    Electronic Resource
    Weinheim : Wiley-Blackwell
    Zeitschrift für anorganische Chemie 357 (1968), S. 11-24 
    ISSN: 0044-2313
    Keywords: Chemistry ; Inorganic Chemistry
    Source: Wiley InterScience Backfile Collection 1832-2000
    Topics: Chemistry and Pharmacology
    Description / Table of Contents: The oxideiodides WO2I2 and WO2I were prepared, for example by reaction of wolfram, wolframtrioxide, and iodine. Their chemical and thermal behaviour is described and informations are given about X-ray studies.The enthalpy of formation ΔH° (WO2I2, c, 298) = -151.9 ± 1.0 kcal/mol is based on measurements of the enthalpy of solution of WO2I2 in a solution of sodium hydroxide.The sublimation pressure of WO2I2 was determined within the temperature range from 255-345°C by means of the effusion method:\documentclass{article}\pagestyle{empty}\begin{document}$$ {\rm log P(WO}_{\rm 2} {\rm I}_{\rm 2},{\rm atm) = } - \frac{{9014(\pm 262)}}{{\rm T}} + 10.711{\rm (} \pm {\rm 0}{\rm .435)} $$\end{document}\documentclass{article}\pagestyle{empty}\begin{document}$$ {\rm ubl}{\rm ., 579 }^ \circ {\rm K) = 41}{\rm .25} \pm {\rm 1}{\rm .2 kcal/mol;}\,\,\,\Delta {\rm S}^{\rm 0} ({\rm subl}{\rm .,579 }^ \circ {\rm K) = 49}{\rm .0} \pm {\rm 2 cl}{\rm .} $$\end{document}
    Notes: Die Oxidjodide WO2J2 und WO2J wurden z. B. aus Wolfram, Wolframtrioxid und Jod dargestellt. Die Verbindungen wurden durch ihr chemisches und thermisches Verhalten sowie röntgenographisch charakterisiert.Die Bildungsenthalpie ΔH° (WO2J2, f, 298) = -151,9 ± 1,0 kcal/Mol wurde aus der Lösungsenthalpie von WO2J2 in Natronlauge ermittelt. Mit der Effusionsmethode erhielt man für den Sublimationsdruck P(WO2J2) zwischen 255-345°C: \documentclass{article}\pagestyle{empty}\begin{document}$$ {\rm log P(WO}_{\rm 2} {\rm I}_{\rm 2},{\rm atm) = } - \frac{{9014(\pm 262)}}{{\rm T}} + 10.711{\rm (} \pm {\rm 0}{\rm .435)} {\rm ubl}{\rm ., 579 }^ \circ {\rm K) = 41}{\rm .25} \pm {\rm 1}{\rm .2 kcal/mol;}\,\,\,\Delta {\rm S}^{\rm 0} ({\rm subl}{\rm .,579 }^ \circ {\rm K) = 49}{\rm .0} \pm {\rm 2 cl}{\rm .} $$\end{document}
    Additional Material: 5 Ill.
    Type of Medium: Electronic Resource
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